Fetch-url-file-3a-2f-2f-2f ((top)) -

if response.status_code == 200: print(response.text) else: print('Failed to fetch URL') Using curl from the command line:

import requests

url = 'http://example.com' response = requests.get(url) fetch-url-file-3A-2F-2F-2F

console.log(decodeURIComponentSafe('3A-2F-2F')); // Outputs: :// from urllib.parse import unquote if response